(x+1)(x+2)(x^2+2)=0

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Solution for (x+1)(x+2)(x^2+2)=0 equation: 


Simplifying
(x + 1)(x + 2)(x2 + 2) = 0

Reorder the terms:
(1 + x)(x + 2)(x2 + 2) = 0

Reorder the terms:
(1 + x)(2 + x)(x2 + 2) = 0

Reorder the terms:
(1 + x)(2 + x)(2 + x2) = 0

Multiply (1 + x) * (2 + x)
(1(2 + x) + x(2 + x))(2 + x2) = 0
((2 * 1 + x * 1) + x(2 + x))(2 + x2) = 0
((2 + 1x) + x(2 + x))(2 + x2) = 0
(2 + 1x + (2 * x + x * x))(2 + x2) = 0
(2 + 1x + (2x + x2))(2 + x2) = 0

Combine like terms: 1x + 2x = 3x
(2 + 3x + x2)(2 + x2) = 0

Multiply (2 + 3x + x2) * (2 + x2)
(2(2 + x2) + 3x * (2 + x2) + x2(2 + x2)) = 0
((2 * 2 + x2 * 2) + 3x * (2 + x2) + x2(2 + x2)) = 0
((4 + 2x2) + 3x * (2 + x2) + x2(2 + x2)) = 0
(4 + 2x2 + (2 * 3x + x2 * 3x) + x2(2 + x2)) = 0
(4 + 2x2 + (6x + 3x3) + x2(2 + x2)) = 0
(4 + 2x2 + 6x + 3x3 + (2 * x2 + x2 * x2)) = 0
(4 + 2x2 + 6x + 3x3 + (2x2 + x4)) = 0

Reorder the terms:
(4 + 6x + 2x2 + 2x2 + 3x3 + x4) = 0

Combine like terms: 2x2 + 2x2 = 4x2
(4 + 6x + 4x2 + 3x3 + x4) = 0

Solving
4 + 6x + 4x2 + 3x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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